HELP WITH PHYSICS QUESTION PLEASE THANK YOU!

Question

An attack helicopter is equipped with a 20- mm cannon that fires 105 g shells in the forward direction with a muzzle speed of 731 m/s. The fully loaded helicopter has a mass of 2360 kg. A burst of 112 shells is fired in a 5.48 s interval. What is the resulting average force on the helicopter? Answer in units of N. By what amount is its forward speed reduced? Answer in units of m/s.

Answer 1

Use the impulse equation to solve for the force exerted on the shells (which by third law must be exerted back on the helicopter:

FΔt = Δmv or F = mv/t and the m is the number of shells x the mass of each shell (Note: put mass in kg)

Once you have F, you can solve for the acceleration of the helicopter: a = F/ M_H (a negative number)

You are then finding Δv = aΔt (the effect on the v of the helicopter.