Power (physics highschool)

Question

An electric motor hoists an elevator, weighing 14.0 kN, 8.00 m in 15.0s at a constant velocity. The motor’s power

output is...? Answer: (7.47 x 104W) please show the process of getting to this answer.

Answer 1

The Work in lifting the elevator is mgh = ΔE_P (or just W= F_Wth

The Power required by the weight being lifted is mgh/t = W/t = Power of the motor if it's 100% efficient

Plug into P = mgh/t mg is the weight in newtons (you have to convert from KN), h in meters, t in seconds.

I believe the answer given is incorrect (I get an exponent of 10³) I think someone forgot that they gave the weight in the problem, not the mass)