Daniel B. answered 01/03/22
A retired computer professional to teach math, physics
Let v = 344 m/s be the speed of sound.
All the possible vibrations will have a node at the closed end,
while the open end will have the maximum oscillation.
Therefore the lowest, fundamental, frequency corresponds to the wave
where only 1/4 of the wavelength fits into the column.
Therefore the wavelength λ = 10m.
The fundamental frequency, f0, is then calculated using the formula
f0 = v/λ = 344/10 = 34.4 Hz
The next higher possible frequency fits a half-wavelength into the column
plus a quarter.
In other words, it fits three time more of into the column than the above.
(If you could draw a picture it would be helpful.)
Therefore the next possible frequency is
f1 = 3f0
The next higher possible frequency fits two half-wavelength into the column
plus a quarter.
In other words, it fits five time more of into the column than the fundamental.
Therefore the next possible frequency is
f2 = 5f0
And so on.
Questions 2. and 3. are about terminology and about counting overtones and harmonics.
Normal terminology considers the fundamental frequency one of the harmonics,
but not one of the overtones.
In question 2. it is not clear to me what the word "first" means.
Using informal English "first overtone" would refer to the above f1.
But some technical terminology calls f1 the third overtone.