∫0x y(t)dt= -x/y(x)
d/dx [ ∫0x y(t)dt ] = - d/dx [x/y(x)]
y(x) = - d/dx [x/y(x)]
y = - 1/y + [ x/y2] [ d y / d x]
d y / d x - (1/ x) y = (1/ x) y3 BERNOULLI
Kyle B.
asked 12/29/21∫0x y(t)dt= -x/y(x)
*difinite integral from 0 to x
∫0x y(t)dt= -x/y(x)
d/dx [ ∫0x y(t)dt ] = - d/dx [x/y(x)]
y(x) = - d/dx [x/y(x)]
y = - 1/y + [ x/y2] [ d y / d x]
d y / d x - (1/ x) y = (1/ x) y3 BERNOULLI
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