Grigoriy S. answered 12/28/21
AP Physics / Math Expert Teacher With 40 Years of Proven Success
In this situation we have two bodies: the person and the Earth. The Earth acts on the person with the force of gravitational attraction that we call weight. Its magnitude W = mg. The person acts on Earth with the force of gravitational attraction F = G mM / R2. Those two forces are equal in magnitude. If you compare them, you can see that g = GM / R2. Actually, not only the person falls on the Earth, but the Earth also "falls" on the person. We do not see this fall only because the mass of the Earth is 10 22 times greater than the mass of an average person. As a result, acceleration of the Earth's "fall" is negligible.
The person is not falling into the Earth core because the surface, which acts on the person with normal reaction force, prevents this from happening. BTW, according to the Newton's third law the person also acts on the surface, and we call this force apparent weight.
Again let me stress: normal reaction force and weight act on a body and if the body is not moving, they cancel each other. But apparent weight applied to the surface or scale and is not cancelled by weight. Weight is a gravitational force and is the same at a given location. Apparent weight is an electromagnetic force and could vary.
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👍🏻12/29/21