Nuraliya S.

asked • 12/26/21

A +3 μC charge and a -1.6 μC charge are placed 18 cm apart. Calculate the electrostatic force acting on the charges.

1 Expert Answer

By:

Nuraliya S.

can u show me the calculation?
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12/26/21

Grigoriy S.

tutor
At first we convert all data to SI q1 = + 3 x 10-6 C q2 = -1.6 x 10 -6 C d = 0.18 m k = 9 x 10 9 Nm2/C2 Let’s substitute in formula F = k q1q2 /d2 all values, then we will have F = 9 x 10 9 (Nm2/C2)∙ 3 x 10-6 C ∙ ( -1.6 x 10 -6) C / (0.18m)2 = - 5.9 x 10-2 N Sign "-" tells us that it is the force of attraction.
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12/28/21

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