Daniel B. answered 12/20/21
A retired computer professional to teach math, physics
The question uses the words "rod" and "crushed".
The latter sounds rather drastic for a solid object like a rod, and analyzing
its crushing would require information about the material.
Therefore I will answer the question after replacing the last sentence with:
"What starting velocity v will cause the rod to experience inward stress at the top point,
and what starting velocity v will cause outward stress?"
I believe the word "light" when applied to rod is supposed to suggest the assumption
that the rod has no mass.
Let
w be the velocity at the top, in those cases when the mass does make it there,
g = 9.81 m/s² be gravitational acceleration.
The kinetic energy of the mass at the bottom is
mv²/2
The kinetic energy of the mass at the top (if it gets there) is
mw²/2
With respect to the bottom, the potential energy of the mass at the top (if it gets there) is
2Lmg
By conservation of energy
2Lmg + mw²/2 = mv²/2
From that
w = √(v²-4Lg)
The mass will make it to the top if the expression for w is defined, that is, if
v² - 4Lg ≥ 0
v ≥ √(4Lg)
Now lets calculate the stress the rod will experience at the top.
It experiences two forces:
- downward gravitational push from the mass, which has magnitude mg,
- upward centrifugal force, which has magnitude mw²/L.
So the direction of their sum will depend on which is larger.
The rod will experience outward stress if
mw²/L > mg
w² > Lg
v²-4Lg > Lg
v > √5Lg
So these are the possible outcomes
0 ≤ v < √4Lg the mass will oscillate
v = √4Lg the mass will get stuck at the top in unstable position
√4Lg < v < √5Lg the mass with rotate and the rod will experience inward stress at the top,
v = √5Lg the mass with rotate and the rod will experience no stress at the top,
v > √5Lg the mass with rotate and the rod will experience outward stress at the top.