
Yefim S. answered 12/17/21
Math Tutor with Experience
2Tsin15° = mg; T = mg/(2sin15°) = 60kg·9.8m/s2/(2sin15°) = 1135.93 N
Elle C.
asked 12/16/21The tightrope walker in the figure below gets tired and decides to stop for rest. During this rest period, she is in equilibrium. She stops at the middle of the rope and notices that both sides of the rope make an angle of 15o below the horizontal. Calculate the tension in the rope on both sides of the tightrope walker. The mass of the tightrope walker is 60.0 kg.
Yefim S. answered 12/17/21
Math Tutor with Experience
2Tsin15° = mg; T = mg/(2sin15°) = 60kg·9.8m/s2/(2sin15°) = 1135.93 N
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