The equations of position with time for the projectile:
y = vy0t -1/2 gt2 and x = vx0t or y in terms of x:
y = (vy0/vx0)x - 1/2 (g/vy02) x2
The incline is given as y = x(tan(φ)) where φ is the angle of the incline.
So you have a quadratic equation in x:
(g/(2vx02)) x2 + ((-vy0/vx0) + tanφ)x = 0 Note that x = 0 is solution. factor out an x and solve.
Note that the ratio of v's is tanθ0 and vx0 = v0cosθ0
Charlotte P.
also i do not know what the variable x is, my teacher uses different letters for variables12/07/21

JACQUES D.
12/08/21
Charlotte P.
i am confused on what y would represent, and I am not sure why vy0t -1/2 gt2 has a minus sign, as when you deal with initial velocity in that equation, it is usually positive.12/07/21