A heat engine uses a heat source at 530 ∘C and has an ideal (Carnot) efficiency of 28 % .

Question

A heat engine uses a heat source at 530 ∘C∘C and has an ideal (Carnot) efficiency of 28 %% .To increase the ideal efficiency to 47 %% , what must be the temperature of the heat source?

Express your answer using two significant figures.

Answer 1

Efficiency = 1 - T2/T1

T1 = Source temp in Kelvin

T2 = Sink temp in Kelvin

0.28 = 1- T2/(530+273)…..eq 1

0.47 = 1 -T2/T1…. eq 2

from eq 1 get T2 and plug in eq 2 to get T1 as new source temp