Grigoriy S. answered 12/02/21
AP Physics / Math Expert Teacher With 40 Years of Proven Success
We have a function f(x) = log 3 (x + 9) – 4 .
Step 1.
We can write y = log 3 (x + 9) – 4
Let’s rewrite it a little bit differently. Because log 10 = 1, we can write
4 = 4 x 1 = 4 log 10 or
4 = log 10 4
Let’s put it in equation for y, then
y = log 3(x + 9) – log 10 4
Using properties of logarithms, it could be written like
y = log (3(x + 9) / 10 4)
Step 2.
Now let’s switch x and y, then we get
x = log (3(y + 9) / 10 4)
Step 3.
Now we have to solve this equation for y. We write
(3(y + 9) / 10 4) = 10 x
Or
( 3y + 27) /10 4 = 10 x
We continue
3y + 27 = 10 4 x 10 x
This is the same as
3y + 27 = 10 x + 4
Moving 27 to the right part of the equation, we obtain
3y = 10 x + 4 - 27
Dividing both part of the equation by 3, we finally have
y = (1/3) 10 x + 4 - 9
Step. 4
Using notation for inverse of the function we can write the answer as
f – 1 (x) = (1/3) 10 x + 4 - 9