Edward C. answered 03/13/15
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Caltech Grad for math tutoring: Algebra through Calculus
The formula for margin of error is m = (z*)*σ/sqrt(n)
For a 95% confidence level z* = 1.96, it is given that σ = 16.5, and you want m <= 5. So
1.96*16.5/sqrt(n) <= 5
sqrt(n) >= 1.96*16.5 / 5
sqrt(n) >= 6.468
n >= 41.8
so take at least 42 samples