William W. answered 11/30/21
Math and science made easy - learn from a retired engineer
If you sketch out where 210° is you will see that it is 30°down from 180° so we can say the reference angle is 30°:
For a 30° angle:
- sin(30°) = 1/2 however, since the sine is like the "y-value" and the y-value is negative in quadrant 3 where 210° is, then sine(210°) = -1/2
- cos(30°) = √3/2 however, since the cosine is like the "x-value" and the x-value is negative in quadrant 3 where 210° is, then cosine(210°) = -√3/2
- tan(30°) = √3/3 and it stays positive in Q3 (since both "x" and "y" values are negative their ratio produces a positive.
Regarding your question "t=3 is found in quadrant 2, what is the reference angle?", I'm unsure what you mean.