plz can u help to solve this with OUBUILD programe

Question

Suppose you have a set of numbers and they are in ascending order such as (6,2,9,5,8,7). In this set we have six pairs that are out of this rule or sequence as following :

(6,2),(6,5),(9,5),(9,8)..etc

1.   You are requested to write an algorithm to display how many numbers which they are out of order.

2.   Build your algorithm by using OUBUILD

3.     Provide two screenshots with different outputs.

Answer 1

def unordered_pairs(list: int): 

  pairs = [] 

  for idx in range(len(list) - 1):  

    for jdx in range(idx + 1, len(list)): 

      if list[idx] > list[jdx]:

        pairs.append( (list[idx], list[jdx]))

             

  print(pairs)

         

unordered= [5,4,7,8,2,3,4,6,1,2,2,6,7,8,3,4,52,1,9]

unordered_pairs(unordered)