given:
mass m = 15kg
from rest = tells us vi velocity initial = 0 m/s
accelerates at a = 4 m/s^2
time t = 25 seconds
distance x = ?
The mass is extra information included to trick you and is not part of the problem. We need to use a, vi, and t to find x. Here is our list of possible kinematics equations:
vf = vi + at
vf^2 = vi^2 + 2ax
x = vit + 1/2at^2
We want an equation with a, vi, t, and x in it = last equation
x = vit + 1/2at^2 plug in our given values
x = (0)(25) + 1/2(4)(25^2)
x = 0 + 1/2*4*625
x = 1250 meters
