Conservation of Momentum:
Initial Momentum = Final Momentum
m1v1 initial + m2v2 initial = m1v1 final + m2v2 final
m1 = 100 grams
m2 = 30 grams
v1 initial = 90 cm/sec
v1 final = 50 cm/sec
v2 initial = at rest = 0 cm/sec
v2 final = ?
We are plugging in our knowns into the equation to find the missing v2 final
*These numbers are not in the correct units but as long as they are all in the same units then your answer will come out with the same units —> all our masses are in grams and all our velocities are in cm/sec so our answer v2 final will come out in cm/sec
(100)(90) + (30)(0) = (100)(50) + (30)v2final
9000 + 0 = 5000 + 30v2final
subtract 5000 from both sides
4000 = 30v2final divide by 30
v2f = 133.33 cm/sec
#2
mass of gun = 5.5 kg
mass of each bullet = 25 g
velocity of each bullet = 200 m/sec
the masses are in different units so I am going to convert grams to kilograms by dividing by 1000
mass each bullet = 0.025 kg
we have 3 objects in this system, one gun and 2 bullets, and all of them are initially not moving
m1 = 5.5 kg
m2 = 0.025 kg
m3 = 0.025 kg
v1 initial = v2 initial = v3 initial = 0 m/sec
v1 final = ?
v2 final = v3 final = 200 m/sec
Plug into the conservation of momentum equation and solve for v1 final
(5.5)(0) + (0.025)(0) + (0.025)(0) = (5.5)v1 final + (0.025)(200) + (0.025)(200)
0 + 0 + 0 = 5.5v1final + 5 + 5
0 = 5.5v1 final + 10 subtract 10 from both sides
-10 = 5.5v1final divide by 5.5
v1 final = - 1.82 m/sec
It makes sense that it’s negative because the gun would go backward to recoil if the bullets are going forward.
Vince Arvi S.
Thank you so much!11/28/21