Gas is confined in a tank at a pressure

Question

Gas is confined in a tank at a pressure of 1.15E+6 Pa and a temperature of 14.2°C. If half of the gas is withdrawn and the temperature is raised to 63.4°C, what is the new pressure in the tank?

Answer 1

P₁V = m/µRT₁; ;

P₂V = m/2µRT₂.

After division we have: P₁/P₂ = 2T₁/T₂; P₂ = P₁·T₂/(2T₁) = 1.15·10⁶Pa·(63.4 + 273.15)K/(14.2+ 273.15)K =

6.73·10⁵ Pa