The weight of a body on the surface the earth is 700N.what will be it weight on the surface of mass whose mass is ⅓ and radius ½ that of the earth..

Answer 1

700 = [ GMM / R^2 ]

X = G(1/3M)(M) / (1/2R)^2

X = (4/3) [GMM / R^2]

X = (4/3) [700]

X = 933