Give the first five terms of the sequence. a1=-40, an=(4+a n-1)(1/2)^n

Answer 1

a_n = (4 + a_n-1)(1/2)ⁿ

given a₁ = -40

a₂ = (4+ a₁)(1/2)² = (4+ (-41))(1/4) = -37/4

a₃ = (4+(-37/4))(1/2)³ = (-21/4)(1/8) = -21/32

following the same algorithm

a₄ = 107/512

a₅ = 2155/16384