Give the first eight terms of the sequence. a1=-1, a2=4, an=a n-2 (3-a n-1)

Answer 1

a_n = a_n-2(3-a_n-1)

a₁=-1

a₂=4

a₃=a₁(3-a₂) = -1(3-4) = 1

a₄=a₂(3-a₃) = 4(3-1) = 8

--- etc ---

Sequence = -1, 4, 1, 8, -5, 64, 305, - 19328