If a ball is thrown from a tall building, how tall is the building if it takes 4s for the ball to land?

Answer 1

The relevant equation to use here is H = V₀ x t + 1/2 x g x t² where H is the height of the building, t the time to reach the ground, V₀ the initial downward velocity, and g the acceleration of gravity.

As it wasn't mentioned otherwise, it is assumed that the ball is thrown horizontally, so V₀= 0.

H = 0 x t + 1/2 x 9.8 m/s² x 4² s² = 78 meters