hits a baseball into the air with an initial vertical velocity of 72 feet per second. player hits ball from height of 3 feet.

Question

question a:write an equation that gives the baseballs height as a function of the time in seconds after it is hit.

question b: after how many seconds is the baseball 84 feet above the ground?

Answer 1

A.) Delta Y= Initial Y+(initial velocity)(time)+0.5(acceleration)(time)^2

B.) With an initial height of 3 feet, the baseball will be 84 feet above the ground after approximately 1.587 seconds.