On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3kg/m3 , length 83.9 cmcm and diameter 2.95 cmcm from a storage room to a machinist.

Question

On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3kg/m3 , length 83.9 cmcm and diameter 2.95 cmcm from a storage room to a machinist. Calculate the weight of the rod, ww. Assume the free-fall acceleration is gg = 9.80 m/s2m/s2 .

Express your answer numerically in newtons.

Answer 1

Hello; Make sure units are consistently in "metres".

First, we find the Volume of the cylinder. V = πr²x h where π = 3.14, r = ( 0.0295 / 2 ) m & h = 0.839m

From here, you should get approximately V = 2.3 x 10^-3 m³

Then, multiply this with the density ρ = 7800 kg/m³

We get the mass ≅ 18 kg

Finally, W = mg = 18 x 9.8 = 176.4N

Make sure I rounded off the numbers, please keep this in mind and calculate yourself again.