Piston 1 in the figure below has a diameter of 0.721 cm;

Question

Piston 1 in the figure below has a diameter of 0.721 cm;

piston 2 has a diameter of 5.02 cm. In the absence of friction, determine the force required on piston 1 necessary to support an object, m, with weight 1124 N. (Neglect the height difference between the bottom of the two pistons, and assume that the pistons are massless).

What is the magnitude of the force, F, required at the end of the handle?

Answer 1

Pressure through the liquid is transmitted without loss. P_piston1 = P_piston2

P = F/A

Area = pi x r² (r = d/2) d = 5.02x10^-2 m

P2 = 1124 / (3.14x[5.02/2 x 10^-2]²

P1 = F/A1 = F/(3.14x[0.721/2 x 10^-2]²

P1 = p2

Canceling the same terms from both sides

The equation boils down to

1124/(5.02)² = F/(0.721)²

Please do the rest....