log3(x2+x-3) = 2

Question

log₃(x²+x-3) = 2

Answer 1

log_ba = x ⇒ b^x = a            This law, and other laws of logarithms, should be learned.

 

log₃(x² + x - 3) = 2

3² = x² + x - 3

9 = x² + x - 3

0 = x² + x - 12                          Now solve for x using FOIL