Vertical asymptotes occur at x-values that make the denominator = 0.
X-intercepts occur at x-values that make the numerator = 0.
The y-intercept is the value of the function when x = 0.
So ... f(x) = [16(x + 6)(x - 5)] / [15(x + 1)(x - 4)]
Lana W.
asked 11/08/21Vertical asymptotes occur at x-values that make the denominator = 0.
X-intercepts occur at x-values that make the numerator = 0.
The y-intercept is the value of the function when x = 0.
So ... f(x) = [16(x + 6)(x - 5)] / [15(x + 1)(x - 4)]
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