Kimberly S.
asked • 03/12/15
solve for y
Namita S.
answered • 03/12/15
Math class at comfort and highly competitive rates
2y2+y+53=(y-5)2
2y2+y+53=y2-10y+25
2y2-y2+y+10y+53-25=0
y2+11y+28=0
y2+7y+4y+28=0
y(y+7)+4(y+7)=0
(y+7)(y+4)=0
y+7=0 or y+4=0
y=-7 or y=-4
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Susan C.
03/12/15