Daniel B. answered 11/06/21
A retired computer professional to teach math, physics
Let
g = 9.81 m/s² be gravitational acceleration,
G = 25g be the target acceleration,
f = 7.75 Hz be the frequency of oscillation,
ω = 2πf be the "angular velocity",
A (to be calculated) be the amplitude.
The position of the oscillating computer as a function of time can be written as
x(t) = Asin(ωt)
If you had calculus then you can calculate the acceleration
a(t) = d²x/dt² = -Aω²sin(ωt)
If you did not have calculus, then I hope you were taught this relation.
So the maximum acceleration is whenever sin(ωt) = ±1.
Equating it to the target acceleration
G = Aω²
A = G/ω² = 25×9.81/(2×π×7.75)² = 0.1 m