
William W. answered 10/29/21
Experienced Tutor and Retired Engineer
Resistors R2 and R3 are in parallel. Their equivalent resistance is calculated from:
So 1/REQ = 1/70 + 1/70 = 2/70 so REQ = 70/2 = 35 Ω
The sum of that resistance and R1 (RTOTAL) is 35 + 125 = 160 Ω
Using I = V/R we calculate that the current flow through R1 is 16/160 = 0.1 A
When that current splits between R2 and R3, it will split in half since R2 = R3 so the current through R2 = 0.1/2 = 0.05A