Mark M. answered 10/26/21
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Retired math prof. Very extensive Precalculus tutoring experience.
sin(2θ) = 2sinθcosθ
Let θ = 3x. Then sin(6x) = 2sin(3x)cos(3x).
Mint F.
asked 10/26/21sin(6x) = 2 sin(3x) cos(3x)
Mark M. answered 10/26/21
Retired math prof. Very extensive Precalculus tutoring experience.
sin(2θ) = 2sinθcosθ
Let θ = 3x. Then sin(6x) = 2sin(3x)cos(3x).
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