(X-3)^2 + 2y^2=8

Question

I need help finding the center, radius and intercepts!

Answer 1

(x - 3)² + 2y² = 8

 

Divide both sides by 8:

 

(x - 3)² + 2y² = 1

    8              8

 

(x - 3)² +  y ² = 1

     8            4            This is the equation of an ellipse with center

                                  (3, 0), NOT a circle.