Centripetal Force (Loop the Loop)

Question

A pilot, whose mass is 79.0 kg, makes a loop-the-loop in a fast jet. Assume that the jet maintains a constant speed of 245 m/s and that the radius of the loop-the-loop is 2.142 km. What is the apparent weight that the pilot feels (i.e., the force with which the pilot presses against the seat) at the bottom of the loop-the-loop?

What is the pilot's apparent weight at the top of the loop-the-loop?

Answer 1

At the bottom of the loop N₁ = mg + mv²/r = 79kg(9.8m/s² + 245²m²/s²/2142m) = 2988 N;

At t5he top of the loop N₂ = mv²/r - mg = 79kg(245²m²/s²/2142m - 9.8m/s²) = 1439.6 N