Degree 3, leading coefficient: -2, zeroes:3,2 +4i

Answer 1

Because complex roots must come in conjugate pairs (for polynomials with real coefficients), 2 - 4i is also a root.

In factored form: f(x) = -2(x - 3)(x - 2 - 4i)(x - 2 + 4i)

Expanding into standard form: f(x) = -2(x - 3)(x² - 4x + 20)

f(x) = -2(x³ - 7x² + 32x - 60) = -2x³ + 14x² - 64x + 120