Find the complement of F=wx+yz, and then show that FF'=0 and F+F'=1 using the axioms and theorems of Boolean algebra.

Answer 1

F = wx + yz

F' = (wx + yz)' = (wx)' . (yz)' = (w'+x') (y'+z')

F.F'= (wx + yz) (w'+x') (y' + z') == 0

F + F' = 1 as 1 + 0 = 1 or 0 + 1 =1