If the area of a triangle is 9 / √ 2 and two of the sides have length 6 and 3, find the angle between these two sides.

Answer 1

Using trigonometry, we know that the area of a triangle is

A = (1/2) * (length of side) * (length of another side) * (sine of the angle between the two sides)

9/√2 = 0.5 * 6 * 3 * sin(ß)

9/√2 = 9 * sin(ß) Divide both sides by 9

1/√2 = sin(ß) Rationalize the denominator

(√2) / 2 = sin(ß)

ß = 45 degrees

Hope this helps!