Let g(x)=-3x2 +ax+1.

Question

Let g(x)=-3x² +ax+1.

Determine the number a such that the tangent line to the curve y=g(x) at the point (4, g(4)) is parallel

to the line y=6x+53.

what is the value of a?

Answer 1

The slope of the tangent line must be 6.

g'(x)=6x+a

g'(4) 24+a = 6 => a=-18