f(1) = 1/2
f'(x) =[ -(1+x) - (2-x) ]/ (1 + x)2 by quotient rule
f'(x) = -3 / (1 + x)2 ; f'(1) = -3/4
Eqn of tangent: y - 1/2 = -3/4(x - 1). y-int: (0 , 5/4)
Amy C.
asked 10/10/21Let f(x)=2−x/1+x
Determine the y-intercept of the tangent line to the graph of f at the point (1, f (1))
f(1) = 1/2
f'(x) =[ -(1+x) - (2-x) ]/ (1 + x)2 by quotient rule
f'(x) = -3 / (1 + x)2 ; f'(1) = -3/4
Eqn of tangent: y - 1/2 = -3/4(x - 1). y-int: (0 , 5/4)
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