
Maria Alejandra P.
asked 10/04/21Show that csc^2 x − sin^2 x / csc x + sin x = cosx cotx
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1 Expert Answer
Mark M. answered 10/05/21
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4.9
(954)
Retired math prof. Very extensive Precalculus tutoring experience.
The left side of the equation is equivalent to [(cscx + sinx)(cscx - sinx)] / (cscx + sinx) = cscx - sinx =
(1 / sinx) - sinx = (1 - sin2x) / sinx = cos2x / sinx = (cosx)(cosx/sinx) = cosxcotx = right side
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Joel L.
10/04/21