A biker passes a lamppost at 4.5 m/s. she accelerates down the hill at a constant rate of .40 m/s^2 for 12 seconds. How far does she move down the hill during this time?

Answer 1

Use Δx = v_o t + 1/2 a t² = (4.5)(12) + (0.20)(12²) = 54 + 29 = 83 m.