An egg is dropped from rest. How fast will it be going just prior to hitting the floor 1.2 m below its release point?

Answer 1

Use the equation:

Where v_f is the final velocity you are looking for, v_i is the initial velocity which is zero in this case, "a" is the acceleration which, in this case is 9.8 m/s², and Δx is the change in height which in this case is 1.2 m

So v_f² = 0² + 2(9.8)(1.2)

v_f = √23.52 = 4.8 m/s