Find the limit with work so i could understand

Question

lim_x->4(x^(2)

-6x+8))

x2-x-12 =

Limx->2

x3 + 8

x+2 =

Lim x-> 3

3x2 -8x-3

x- 3 =

Answer 1

The first and third limits have the indeterminate form 0/0. For each one, factor the numerator and denominator, cancel out the common factor, and then plug in the appropriate value. The second limit can be evaluated as written by plugging in. If there is a typo and you are supposed to find the limit as x approaches -2, then that limit also has the form 0/0 which would then be done in the same manner as the other two problems.