
William W. answered 09/22/21
Experienced Tutor and Retired Engineer
I believe this sketch matches your problem;
Split vector A into its components:
Ax = 30cos(30°) = 25.98 (going west)
Ay = 30sin(30°) = 15 (going south)
Since the resultant has no x-component (it's straight up toward north), then Bx must be the same magnitude but opposite direction to Ax so Bx = 25.98 (east).
For the y-direction, Ay + By must equal the Resultant (since it is only in the y-direction). Since Ay is going south, we can call its value -15. So -15 + By = 40 or By = 55
Since Bx = 25.98 and By = 55, the magnitude of B = √(25.982 + 552) = √3700 = 60.83 m.
To find the direction, use tan(θ) = Bx/By = 25.98/55 so θ = tan-1(25.98/55) = 25.3° west of north