George C. answered 09/23/21
Physics , TOEFL and Trigonometry Teacher
a = Fk / m = 0.410 * (500*10 / 0.530 ) / 500
= 7.73 m/s2
tan angle = 7.73 / 9.8 = 0.7887
Angle = 38.26 degree
Sharon G.
asked 09/22/21A 500 kg block sits on a horizontal tabletop. The coefficient of static and kinetic friction are 0.530 and 0.410 respectively, at the contact surface between table and block. An external force of 10.0 N is applied at an angle with the horizontal. What angle will lead to the maximum acceleration of the block given the external force? What is the maximum acceleration?
George C. answered 09/23/21
Physics , TOEFL and Trigonometry Teacher
a = Fk / m = 0.410 * (500*10 / 0.530 ) / 500
= 7.73 m/s2
tan angle = 7.73 / 9.8 = 0.7887
Angle = 38.26 degree
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