Suppose a piece of glass dropped near the top of the hotel falling 215 meters. Ignoring air resistance, what will the velocity in m/s of the piece of glass be when it strikes the ground?

Answer 1

Use the equation (valid for dropping, i.e., initial velocity is zero):

v² = 2ax where "v" is the velocity of the object when it hits the ground, "a" is the acceleration due to gravity which is 9.8 m/s², and "x" is the height (or distance to the ground)

So v² = 2(9.8)(215)

Multiply and then take the square root to get "v"