Maike J.
asked 03/09/15focal length immersed in water
1 Expert Answer
For a thin lens, the focal length depends on the refractive index difference between the lens and the surrounding medium:
1/f ∝ (n_lens / n_medium − 1)
In air:
n_lens = 1.54
n_air ≈ 1
So,
(n_lens / n_air − 1) = (1.54 / 1 − 1) = 0.54
Since f_air = 40 cm, we have:
1/f_air ∝ 0.54
In water:
n_water = 1.33
(n_lens / n_water − 1) = (1.54 / 1.33 − 1)
= 1.158 − 1
= 0.158
So,
1/f_water ∝ 0.158
Taking the ratio:
f_water / f_air = 0.54 / 0.158
= 3.42
Therefore,
f_water = 40 × 3.42
= 136.8 cm
Final Answer:
The focal length in water is approximately 137 cm (about 1.37 m).
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