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Question

The elevation​ E, in​ meters, above sea level at which the boiling point of a certain liquid is t degrees Celsius is given by the function shown below. At what elevation is the boiling point 109.5°​? 110°​? E(t)=1300(110−t)+540(110−t)2

At what elevation is the boiling point 109.5°​?

​E(109.5°​)= how many meters?

Answer 1

Plug into the equation as it is. If you plug in 110, you get E = 0 (It is the normal boiling point of the liquid.)

109.5 --> 1300(110-109.5) + 540(110 - 109.5)²

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