What is the equation of line j?

Question

Line g is represented by the equation y=-4/5x+1. Line j is the equation perpendicular to line g and passes through the point (-10,0). What is the equation of line j? 

Answer 1

perpendicular lines have slopes that are negative reciprocals of each other

y=(-4/5)x+1 is line g

line j has slope (5/4) and goes through point (-10,0)

y=mx+b

y=(5/4)x+b so far

0=(5/4)(-10)+b

0=-50/4+b

0=-25/2+b

b=25/2, the y-intercept

y=(5/4)x+25/2 is the equation of the line