Please help ((( correct answers only ))))

Question

The position of a particular particle as a function of time is given by r⃗ = ( 9.60ti^ + 8.85j^ - 1.00t2k^)m, where t is in seconds.

Part A

Determine the particle's velocity as a function of time. Express your answer in terms of the unit vectors i^, j^, and k^.

v⃗ = _________ m/s

Part B

Determine the particle's acceleration as a function of time. Express your answer in terms of the unit vectors i^, j^, and k^.

a⃗ = ________________ m/s²

Answer 1

as we know , dr/dt=dv , for solving you have to know basics derivatives and kinematics .

d(9.6ti^+ 8.85tj^ -1t^2k^)/dt as we know single function derivative will be a constant function. fo9.6

v=9.6i^+0j^ -2tk^ and derivative of constant is o. like here 8.85 is constant so their derivative

is zero. in k^ there is t^2 so there derivatives in 2t .