Mark M. answered 09/18/21
Retired math prof. Very extensive Precalculus tutoring experience.
Since f(x) is a linear function, f(x) = ax + b, for some real numbers a and b.
Since f(x+5) - f(x) = 6, we have [a(x+5) + b] - (ax + b) = 6. So, 5a = 6. Therefore, a = 6/5.
So, f(x) = (6/5)x + b
Find f-1(x):
y = (6/5)x + b
Switch x and y to get x = (6/5)y + b
Solve for y: x - b = (6/5)y
So, y = f-1(x) = (5x - 5b) / 6
f-1(x+4) - f-1(x) = [5(x+4) - 5b] / 6 - (5x - 5b) / 6 = 20/6 = 10/3