Seems like you need more information in order to do the problem. Usually, you have 4 pieces of info for the compound microscope (like magnification or fo = do,o). Here you're trying to solve for fo sol you can't assume that the object is at the focal length. However, you can do this for the eyepiece and using the near point:
Assume that me = 25 cm/fe = 4.8077
Now you can assume that the magnification for the eyepiece is correct, but the positioning is such that the real image cast by the objective will be positioned inside the focal length of the eyepiece so that di,e/do,e = me that we have approximated. (All length in cm)
di,e = - 4.8077do,e
You can now solve for do,e: 1/fe = 1/do,e - 1/(4.8077di,e)
Once you have this, you can solve for fo: 1/fo = 1/do + 1/(16.2-do,e) (both do and di are positive for objective and the image is real, inverted, and magnified)
I get 1.017 cm which is close to 1.11 cm
Take care and please consider a tutor.